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'''
Draft a python script to solve the following questions. thanks
# Requirement
Please use recursion to define and test a function to calculate the sum of a list of numbers.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def list_sum_Recur(num_list):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
import sys
sys.setrecursionlimit(999999)
def list_sum_Recur(num_list):
# implementation here
if len(num_list) == 1:
return num_list[0]
else:
return num_list[0] + list_sum_Recur(num_list[1:])
# test here
def test_list_sum_Recur():
print(list_sum_Recur([1, 2, 3, 4, 5]))
print( (1+5)*5 / 2)
print(list_sum_Recur(list(range(1,9999+1))))
print( (1+9999)*9999 / 2)
test_list_sum_Recur()

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'''
Draft a python script to solve the following questions. thanks
# Background
The greatest common divisor (GCD) of integers a and b, at least one of which is nonzero, is the greatest positive integer d such that d is a divisor of both a and b; that is, there are integers e and f such that a = de and b = df, and d is the largest such integer. The GCD of a and b is generally denoted gcd(a, b).[8]
When one of a and b is zero, the GCD is the absolute value of the nonzero integer: gcd(a, 0) = gcd(0, a) = |a|.
This case is important as the terminating step of the Euclidean algorithm.
The above definition is unsuitable for defining gcd(0, 0), since there is no greatest integer n such that 0 × n = 0.
However, zero is its own greatest divisor if greatest is understood in the context of the divisibility relation,
so gcd(0, 0) is commonly defined as 0.
This preserves the usual identities for GCD, and in particular Bézout's identity,
namely that gcd(a, b) generates the same ideal as {a, b}.[9][10][11]
This convention is followed by many computer algebra systems.[12]
Nonetheless, some authors leave gcd(0, 0) undefined.[13]
# Requirement
Please use recursion to define and test a function to find the greatest common division of two positive integers.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def gcd_Recur(a,b):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
lteration = 0
def gcd_Recur(a,b):
# implementation here
global lteration
# https://proofwiki.org/wiki/GCD_for_Negative_Integers
if a < 0 or b < 0:
print("Conservative result: tested number more reasonable if greater than 1")
if a == 0 and b == 0:
return 0
if b == 0:
return a
else:
lteration+=1
return gcd_Recur(abs(b), abs(a % b))
# test here
def test_gcd_Recur():
global lteration
input_list = [
# from wiki: gcd(54,24) = 6
(54,24),
# from wiki: gcd(8, 12) = 4
(8,12),
# for no gcd
(5,7),
(-12,3), (-12,0),(12,-1),
# https://en.wikipedia.org/wiki/Greatest_common_divisor
# from wiki: gcd(0, 0) is commonly defined as 0
(0,0),
# https://en.wikipedia.org/wiki/Greatest_common_divisor
# from wiki: When one of a and b is zero, the GCD is the absolute value of the nonzero integer: gcd(a, 0) = gcd(0, a) = |a|.
(0,6), (1,0),
(0,88),(99,0)]
for a,b in input_list:
lteration = 0
print("gcd of ", a, " and ", b, " is: ", gcd_Recur(a,b))
test_gcd_Recur()

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'''
Draft a python script to solve the following questions. thanks
# Background
In mathematics, the harmonic series is the infinite series formed by summing all positive unit fractions.
# Requirement
Please use recursion to define and test a function to calculate the harmonic series upto `n` terms.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def gcd_Recur(a,b):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
import sys
sys.setrecursionlimit(999999)
lteration = 0
def harmonic_series_Recur(n):
# implementation here
global lteration
# https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)
if lteration == 0 and n < 1:
return "Error: n should equal or lager than 1"
if lteration == 0 and n == 0:
return 1
if n == 1:
return 1
else:
lteration +=1
return 1/n + harmonic_series_Recur(n-1)
# test here
def test_harmonic_series_Recur():
global lteration
n_list = [-10,-1,0,1,5, 99, 9999]
for n in n_list:
print("result of ", n, ' is : ', harmonic_series_Recur(n))
lteration = 0
if __name__ == '__main__':
test_harmonic_series_Recur()

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'''
Draft a python script to solve the following questions. thanks
# Requirement
Please use recursion to define and test a function to calculate the value of 𝑥 to the power of `n`.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def power_Recur(x,n):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
import sys
sys.setrecursionlimit(10000)
def power_Recur(x,n):
# implementation here
if n == 0:
return 1
else:
return x * power_Recur(x, n-1)
# test here
def test_power_Recur():
input_list = [
(0, 0),
(0, 3),
(3, 0),
(2, 3),
(-2, 3),
(-2, 4),
(10, 10),
(10, 99),
]
for x, n in input_list:
result = power_Recur(x, n)
print("x:",x,"n:",n, " result : ", result, ",len of answer", len(str(result)))
test_power_Recur()

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'''
Draft a python script to solve the following questions. thanks
# Requirement
Please use recursion to define and test a function to accept a decimal integer and display its binary equivalent.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def Dec2Binary_Recur(num):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
def Dec2Binary_Recur(num):
# implementation here
if num > 1:
return Dec2Binary_Recur(num // 2) + str(num % 2)
else:
return str(num % 2)
# test here
def test_Dec2Binary_Recur():
num_list = [ 1,32,64,128,255]
for num in num_list:
temp = Dec2Binary_Recur(num)
print('result of DEC', str(num).zfill(4), ' is :',(8 - len(temp))*'0'+temp)
if __name__ == '__main__':
test_Dec2Binary_Recur()

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'''
Draft a python script to solve the following questions. thanks
# Requirement
Please use recursion to define and test a function to take in a string and returns a reversed copy of the string.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def reverse_Recur(a,b):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
def reverse_Recur(a, b):
# implementation here
if len(a) == 0:
return b
else:
return reverse_Recur(a[1:], a[0] + b)
# test here
test = ''''''
print("test string:")
print(test)
print("reversed:")
print(reverse_Recur(test, ""))
print()
print()
test = '''helloworld'''
print("test string:")
print(test)
print("reversed:")
print(reverse_Recur(test, ""))
print()
print()
test = '''The exponent is usually shown as a superscript to the right of the base. In that case, bn is called "b raised to the nth power", "b (raised) to the power of n", "the nth power of b", "b to the nth power",[2] or most briefly as "b to the n(th)".'''
print("test string:")
print(test)
print("reversed:")
print(reverse_Recur(test, ""))

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'''
Draft a python script to solve the following questions. thanks
# Requirement
Please use recursion to define and test a function to check whether a number is Prime or not.
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
- write your code in `def isPrime_Recur(a,b):` , with comment `# implementation here`
- write a sample function to use it, with comment `# test here`
'''
import sys
sys.setrecursionlimit(999999)
def isPrime_Recur(a,b):
# implementation here
# https://t5k.org/notes/faq/negative_primes.html
if a < 0:
return "tested number should be greater than 1"
# https://corp.tutorocean.com/is-1-a-prime-number/
if a == 0 or a == 1:
return "Conservative result: tested number is neither prime nor composite"
if b == 1:
return True
if a % b == 0:
return False
else:
return isPrime_Recur(a,b-1)
# test here
if __name__ == '__main__':
num_list = [-99, -3, -1, 0, 1, 3, 7, 9, 9999, 10007]
for num in num_list:
print('is ', num, ' Prime?', isPrime_Recur(num, num-1))

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P01
https://leetcode.com/playground/gZTt9LMe
P02
https://leetcode.com/playground/CsnfvkZe
P03
https://leetcode.com/playground/Ga3kggri
P04
https://leetcode.com/playground/R6Xh2hnB
P05
https://leetcode.com/playground/8DPfAMSb
P06
https://leetcode.com/playground/CsnfvkZe
P07
https://leetcode.com/playground/H9BecSM9

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assignment02_Q01_4086741
Q01:
Please use recursion to define and test a function to calculate the sum of a list of numbers.
A01:
---
assignment02_Q02_4086741
Q02:
A02:
---
assignment02_Q03_4086741
Q03:
A03:
---
assignment02_Q04_4086741
Q04:
A04:
---
assignment02_Q05_4086741
Q05:
A05:
---
assignment02_Q06_4086741
Q06:
A06:
---
assignment02_Q07_4086741
Q07:
A07:
---

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'''
Draft a python script to solve the following questions. thanks
# Requirement
Count down a nonnegative number to zero
n,n— 1, n — 2, ...,0
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
'''
def countdown(n):
"""
Count down a nonnegative number to zero
"""
if n == 0:
print(n)
else:
print(n)
countdown(n-1)
if __name__ == '__main__':
countdown(5)

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'''
Draft a python script to solve the following questions. thanks
# Requirement
Calculate the factorial Of a nonnegative integer where
n! = n * (n - 1) * (n - 2) * ... * 2 * 1 and 0 != 1
# procedure
- let's think it step by step
- leave me comment with your code
- solve with recursion
'''
def factorial(n):
"""
Calculate the factorial Of a nonnegative integer where
n! = n * (n - 1) * (n - 2) * ... * 2 * 1 and 0 != 1
"""
if n == 0 or n == 1:
return 1
else:
return n * factorial(n-1)