update max015,

T11/gpt_answer/main.md

@@ -0,0 +1,36 @@
+Let's break down the code step by step:
+
+1. The function `my_function` takes an integer `n` as input.
+
+2. The function checks if `n` is equal to 1. If it is, the function returns without doing anything.
+
+3. If `n` is not 1, the function uses two nested for loops:
+
+   - The outer loop iterates from 1 to `n` (inclusive).
+   - The inner loop iterates from 1 to `n` (inclusive).
+
+4. Inside the inner loop, it prints a single asterisk (`*`) followed by a newline (`\n`).
+
+Now, let's analyze the time complexity using Big-O notation:
+
+- The outer loop runs `n` times, and for each iteration, the inner loop runs `n` times.
+- Therefore, the total number of iterations is `n * n`, which simplifies to `n^2`.
+
+Since the number of operations (printing asterisks) is proportional to `n^2`, the time complexity is O(n^2).
+
+Here's the corrected code with the additional newline character (`\n`) at the end of the inner loop:
+
+```python
+def my_function(n):
+  if n == 1:
+    return
+
+  for i in range(1,n+1):
+    for j in range(1, n+1):
+      print("*", end="")
+      print()  # Add a newline character
+
+my_function(5)
+```
+
+When you run this code, it will print a 5x5 grid of asterisks, each on a new line.