max015/T11/gpt_answer/main.md

Let's break down the code step by step:

1. The function my_function takes an integer n as input.

2. The function checks if n is equal to 1. If it is, the function returns without doing anything.

3. If n is not 1, the function uses two nested for loops:

   • The outer loop iterates from 1 to n (inclusive).
   • The inner loop iterates from 1 to n (inclusive).

4. Inside the inner loop, it prints a single asterisk (*) followed by a newline (\n).

Now, let's analyze the time complexity using Big-O notation:

• The outer loop runs n times, and for each iteration, the inner loop runs n times.
• Therefore, the total number of iterations is n * n, which simplifies to n^2.

Since the number of operations (printing asterisks) is proportional to n^2, the time complexity is O(n^2).

Here's the corrected code with the additional newline character (\n) at the end of the inner loop:

def my_function(n):
  if n == 1:
    return

  for i in range(1,n+1):
    for j in range(1, n+1):
      print("*", end="")
      print()  # Add a newline character

my_function(5)

When you run this code, it will print a 5x5 grid of asterisks, each on a new line.